tugas 05/sep/2022

 129.40.0.0/18

IIIIIIII IIIIIIII II000000 00000000

Tentukan : 1. Subnet

                    2. host subnet

                    3. host valid

                    4. netmask

                    5. rentang ip address berdasarkan subnet

                    6. blok subnet

jawaban: 

1.) 2^x = 2^2 = 4 subnet

2.) 2^y - 2^6 = 64 host subnet

3.) 2^y - 2 = 2^6 - 2 = 64 - 2 = 62 host

4.) 256 - 192 = 64

5. 0, 16, 32, 48, 69, 96, 112, 128, 160, 176, 192, 208, 224, 230

6.) 256 - 2^y = 256 - 2^6 = 256 - 64 = 192

Network : 129.40.0.0

I : 129.40.0.1

Address : 129.40.63.254

Bc : 129.40.63.255

Network : 129.40.64.0

I : 129.40.64.1

Address : 129.40.127.254

Bc : 129.40.127.255

Network : 129.40.128.0

I. : 129.40.128.1

Address : 129.40.191.254

Bc : 129.40.191.255

Network : 129.40.192.0

I : 129.40.192.1

Address : 129.40.255.254

Bc : 129.40.255.255